Lists that go up or down by the same amount each time: find any term, and the sum of the first n terms.
| nth term | an = a + (n − 1)d |
| Sum of n terms | Sn = n ÷ 2 × [2a + (n − 1)d] |
| Sum with the last term l | Sn = n ÷ 2 × (a + l) |
| nth term from the end | l − (n − 1)d |
How many terms of the AP 14, 18, 22, … must be taken to give a sum of 1,440?
Working: n/2 × (28 + (n − 1) × 4) = 1440; the positive solution is n = 24
Answer: 24 terms