The zeroes of a polynomial are where its graph meets the x-axis, and for a quadratic they are tied to the coefficients by two simple rules.
| Sum of zeroes (quadratic) | α + β = −b/a |
| Product of zeroes (quadratic) | αβ = c/a |
| Quadratic from its zeroes | k[x2 − (α + β)x + αβ] |
| Useful identity | α2 + β2 = (α + β)2 − 2αβ |
Find the zeroes of 6y2 − 25y + 25 and verify the relationship between the zeroes and the coefficients.
Working: 6y2 − 25y + 25 = (2y − 5)(3y − 5); sum = 25/6 = −b/a, product = 25/6 = c/a
Answer: 5/3 and 5/2