Equations of the form ax2 + bx + c = 0: solve by factorising or the quadratic formula, and use the discriminant to tell what kind of roots there are.
| Quadratic formula | x = (−b ± √(b2 − 4ac)) ÷ 2a |
| Discriminant | D = b2 − 4ac |
| D > 0 | two distinct real roots |
| D = 0 | two equal real roots, each −b ÷ 2a |
| D < 0 | no real roots |
Solve: x + 18/x = 9 (x ≠ 0)
Working: multiply by x: x2 − 9x + 18 = 0, so (x − 6)(x − 3) = 0
Answer: x = 3 or x = 6