The distributive law splits a hard product into easy ones. The same idea counts fares, schedules and seats step by step.
| Distributive law | a(b + c) = ab + ac; a(b − c) = ab − ac |
| Example | 98 × 15 = 1,500 − 30 = 1,470 |
| Difference of squares | (a + b)(a − b) = a2 − b2: 53 × 47 = 2,500 − 9 = 2,491 |
| Square of a sum | (a + b)2 = a2 + 2ab + b2: 522 = 2,704 |
| Shortcut | (x + y)2 − (x − y)2 = 4xy |
| Common factor | m + 2m + … + nm = m × n(n + 1) ÷ 2 |
| Two brackets | (r + k)(c + m) = rc + rm + kc + km |
A train runs from P to S, stopping at Q and R. 60 passengers board at P. At Q, 30 get off and 45 get on. At R, 30 get off and 10 get on. Everyone left gets off at S. A ticket costs ₹25 from P to Q, ₹20 from Q to R and ₹20 from R to S, for each stretch travelled. How many passengers travel (a) from Q to R (b) from R to S?
Working: 60 − … at each station: subtract those who get off, add those who get on
Answer: (a) 75; (b) 55