Algebraic identities are true for every value of the letters. They speed up squaring, cubing and factorising.
| Squares | (a + b)2 = a2 + 2ab + b2; (a − b)2 = a2 − 2ab + b2 |
| Difference of squares | a2 − b2 = (a + b)(a − b) |
| Three terms | (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca |
| Cubes | (a + b)3 = a3 + b3 + 3ab(a + b); (a − b)3 = a3 − b3 − 3ab(a − b) |
| Sum and difference of cubes | a3 + b3 = (a + b)(a2 − ab + b2); a3 − b3 = (a − b)(a2 + ab + b2) |
Without cubing, find 103 + 63 + (−16)3.
Working: the numbers add to 0, so the sum of cubes is 3 × 10 × 6 × (−16)
Answer: −2880