In an arithmetic progression each term is the last one plus a fixed number d. Find any term, or the sum of many terms, with two formulas.
| nth term | an = a + (n − 1)d |
| Sum of n terms | Sn = n/2 × (2a + (n − 1)d) |
| Sum from first and last term l | Sn = n/2 × (a + l) |
| A term from the sum | an = Sn − Sn−1 |
How many terms of the AP 14, 18, 22, … must be taken to give a sum of 1,440?
Working: n/2 × (28 + (n − 1) × 4) = 1440; the positive solution is n = 24
Answer: 24 terms