Standard difficulty · 20 questions · 40 marks
Show your working for Sections B and C. Answers are on the last page — try every question first!
Biomolecules · AW-12C-BIO-2026-V1 · For parents — fold back or tear off before handing the sheet to your child.
| Q | Answer | Working |
|---|---|---|
| 1 | (d) aldohexose | — |
| 2 | (c) monosaccharide (aldohexose) | — |
| 3 | (a) beriberi | vitamin B1 (thiamine) is water-soluble |
| 4 | (a) 34% | Chargaff: A = T = 16%; G = C = (100 − 32)/2 = 34% |
| 5 | (c) 7 | each new peptide bond joins two residues and releases one water molecule |
| 6 | (c) glucose cyanohydrin | — |
| 7 | (a) 3′-GGUGGUGG-5′ | A → U, T → A, G → C, C → G |
| 8 | (a) Both A and R are true, and R is the correct explanation of A. | A is true: it has a free aldehyde or ketone (hemiacetal) group. R is true and explains A. |
| 9 | Sugars that reduce Fehling's solution and Tollens' reagent because they have a free aldehyde or ketone (hemiacetal) group. Examples: glucose, fructose, maltose, lactose. | — |
| 10 | 3′-AAUUGGAGAUGG-5′ | A → U, T → A, G → C, C → G; the mRNA runs antiparallel to the template |
| 11 | 32 | A–T pairs have 2 hydrogen bonds, G–C pairs 3: 4 × 2 + 8 × 3 |
| 12 | 518 g/mol | 147 + 146 + 133 + 146 − 3 × 18 |
| 13 | lactose: disaccharide, reducing, glucose and galactose; maltose: disaccharide, reducing, two glucose units | — |
| 14 | vitamin B12; water-soluble | A, D, E and K are fat-soluble; B and C are water-soluble |
| 15 | 144 g | C12H22O11 + H2O → C6H12O6 (glucose) + C6H12O6 (fructose); 0.8 mol of each |
| 16 | 120 | 6 × 5 × 4 |
| 17 | Open chain: HI gives n-hexane (six carbons in a straight chain); acetylation gives a pentaacetate (five –OH groups); HCN and hydroxylamine react (a carbonyl group); bromine water gives gluconic acid (an aldehyde). But glucose does not give Schiff's test or form a bisulphite compound, and its pentaacetate does not react with hydroxylamine; it exists as two forms (α and β) with different rotations. So it exists mainly as a six-membered ring (pyranose) formed by the C-5 –OH adding to the aldehyde. | — |
| 18 | (a) 3′-CCGTGCGAG-5′; (b) 3′-CCGUGCGAG-5′; (c) 25; (d) 22.22% | A–T: 2 H-bonds, G–C: 3; each base pair has the same A + T share on both strands |
| 19 | (a) 4; (b) 516 g/mol; (c) 120 | 5! orders; mass = sum − 4 × 18 |
| 20 | sucrose: disaccharide, non-reducing, glucose and fructose; maltose: disaccharide, reducing, two glucose units; Tollens' or Fehling's test: only the reducing sugar (maltose) gives a positive result | reducing sugars reduce Tollens' and Fehling's reagents |