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CBSE · Class 4 · Mathematics

The Transport Museum

Standard difficulty · 20 questions · 40 marks

Name: Date: Score: ____ / 40

Show your working for Sections B and C. Answers are on the last page — try every question first!

Section A — Choose the correct answer8 × 1 = 8 marks
1.
26 × 100 = ?
  1. 260
  2. 26000
  3. 126
  4. 2600
2.
47 × 28 = ?
  1. 1316
  2. 1326
  3. 1288
  4. 846
3.
150 ÷ 14 gives:
  1. quotient 10, remainder 11
  2. quotient 11, remainder 0
  3. quotient 9, remainder 10
  4. quotient 10, remainder 10
4.
230 ÷ 10 = ?
  1. 2300
  2. 24
  3. 23
  4. 33
5.
14 × 10 =
  1. 24
  2. 14
  3. 140
  4. 1400
6.
50 × 60 = ?
  1. 30
  2. 3000
  3. 300
  4. 30000
7.
In the table of 16, what is 16 × 3?
  1. 38
  2. 58
  3. 48
  4. 49
8.
14 × 400 = ?
  1. 5600
  2. 56
  3. 560
  4. 56000
Section B — Short answer8 × 2 = 16 marks
9.
22 × 62 = ___
10.
384 × 42 = ___
11.
Divide 330 by 14. Write the quotient and the remainder.
12.
9800 ÷ 100 = ___
13.
87 × 300 = ___
14.
Write the table of 17 from 17 × 1 to 17 × 5.
15.
760 ÷ 20 = ___
16.
A museum ticket costs Rs 384. How much do 8 tickets cost?
Section C — Word problems4 × 4 = 16 marks
17.
438 children are going to the transport museum. Each bus has 48 seats. How many buses are needed? How many seats will be empty?
18.
Adult tickets cost Rs 775 and child tickets Rs 630. A group buys 14 adult and 10 child tickets. What is the total cost?
19.
A worker earns Rs 18 for each brick wall section. One month he builds 234 sections. How much does he earn?
20.
432 bottle caps are shared equally among 25 children. How many does each child get? How many are left over?
AmbifulWorksheets
Practice that never repeats
CBSE · Class 4 · Mathematics

Answer key

The Transport Museum · AW-4M-TRM-2026-V1 · For parents — fold back or tear off before handing the sheet to your child.

QAnswerWorking
1(d) 260026 hundreds
2(a) 131647 × 20 + 47 × 8
3(d) quotient 10, remainder 1014 × 10 = 140; 150 − 140 = 10
4(c) 23—
5(c) 14014 tens
6(b) 30005 × 6 = 30, then two zeros
7(c) 4816 × 3 = 10 × 3 + 6 × 3
8(a) 560014 × 4 = 56, then × 100
9136420 × 60 + 20 × 2 + 2 × 60 + 2 × 2
1016128use the box method: split both numbers into hundreds, tens and ones
11quotient 23, remainder 814 × 23 = 322
1298—
132610087 × 3 × 100
1417, 34, 51, 68, 85—
1538760 ÷ 10 ÷ 2
16Rs 3,072384 × 8
1710 buses; 42 empty seats438 ÷ 48 = 9 remainder 6, so one more bus
18Rs 17,15014 × 775 + 10 × 630
19Rs 4,212234 × 18
2017 each; remainder 725 × 17 = 425