Standard difficulty · 20 questions · 40 marks · Time: 37 minutes
Show your working for Sections B and C. Answers are on the last page — try every question first!
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| Q | Answer | Working |
|---|---|---|
| 1 | (d) a × b + a × c | — |
| 2 | (a) 3,920 | 40 × (100 − 2) = 4,000 − 80 |
| 3 | (d) 9,984 | (100 + 4)(100 − 4) = 1002 − 42 = 10,000 − 16 |
| 4 | (a) 140 | A 20 days, B 27 − 4 = 23 days, C 27; 2 × (20 + 23 + 27) |
| 5 | (c) 5,200 | 110 × 20 + 100 × 25 + 100 × 5 |
| 6 | (d) 156 | the expression always equals 2(ad + bc) for (a + b)(c + d) − (a − b)(c − d): 2(14 × 3 + 4 × 9) |
| 7 | (c) 43,264 | (200 + 8)2 = 40,000 + 2 × 200 × 8 + 64 |
| 8 | (a) 425 | 242 − 1 = 575; 575 − 5 × 2 × 6 = 515 > 287.5, so − 5 × 3 × 6 = 425 |
| 9 | 44 = 40 + 4, and multiplying a sum means multiplying each part and adding (the distributive law). | — |
| 10 | 594 | 66 × (10 − 1) = 660 − 66 |
| 11 | 8,019 | 902 − 92 = 8,100 − 81 |
| 12 | (a) 39; (b) 40 | A: count the working days week by week; B: 53 − 13 |
| 13 | (a) 75; (b) 55 | 60 − … at each station: subtract those who get off, add those who get on |
| 14 | 504 | (a + b)2 − (a − b)2 = 4ab = 4 × 14 × 9 |
| 15 | 403 | (22 + 1)(22 − 1) = 222 − 1 = 483; 483 − 2 × 5 × 8 |
| 16 | 3,402 | 9 × (1 + 2 + … + 27) = 9 × 378 |
| 17 | (a) 40; (b) 45; (c) 695 | 5 × (40 + 45 + 54) = 695 |
| 18 | (a) 150; (b) 165; (c) ₹9,100 | 140 × 20 + 150 × 20 + 165 × 20 |
| 19 | (a) ₹2,160; (b) ₹108; (c) ₹2,052 | 18 × 120 − 18 × 6 = 18 × 114 |
| 20 | (a) 126; (b) 285; (c) 159 | 126 + 45 + 84 + 30 |