Standard difficulty · 20 questions · 40 marks · Time: 36 minutes
Show your working for Sections B and C. Answers are on the last page — try every question first!
Sets (Advanced) · AW-9M-AST-2026-V1 · For parents — fold back or tear off before handing the sheet to your child.
| Q | Answer | Working |
|---|---|---|
| 1 | (d) 256 | n[P(A)] = 28 = 256 |
| 2 | (d) 20 | n(A ∪ B) = 48 − 1 = 47; n(A ∩ B) = 37 + 30 − 47 = 20 |
| 3 | (d) every set | φ has no element that could fail to be in another set |
| 4 | (a) 24 | A − B is the part of A ∪ B outside B: 63 − 39 = 24 |
| 5 | (c) 34 | n(A) = 26, n(B) = 11, A ∩ B = multiples of 21: 3; 26 + 11 − 3 = 34 |
| 6 | (b) in A but not in B | A − B = {x : x ∈ A and x ∉ B} |
| 7 | (d) 49 | n(A ∪ B) ≤ 140, so n(A ∩ B) ≥ 73 + 116 − 140 = 49 |
| 8 | (a) 65 | 35 + 40 − 2 × 5 = 65 |
| 9 | A ∪ B = {1, 3, 8, 9, 12, 13, 15, 16}; A ∩ B = {1, 9, 13}; A − B = {15, 16}; (A ∪ B)′ = {2, 4, 5, 6, 7, 10, 11, 14} | (A ∪ B)′ is everything in U outside A ∪ B |
| 10 | P = {φ, {d}, {x}, {z}, {d, x}, {d, z}, {x, z}, {d, x, z}}; 7 proper subsets | 23 = 8 subsets; all but the set itself are proper: 8 − 1 = 7 |
| 11 | A′ = {1, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25}; n(A′) = 16 | n(A) = 9, so n(A′) = 25 − 9 = 16 |
| 12 | (a) 16; (b) 30; (c) 9 | n(A ∩ B) = 46 + 25 − 55 = 16; then 46 − 16 and 25 − 16 |
| 13 | 6 | 80% + 55% − 40% = 95% do at least one, so 5% of 120 = 6 |
| 14 | (a) 9; (b) 6 | 29 − 26 = 26(23 − 1) = 448, so 26 = 64 |
| 15 | 27 | sum of the three = exactly one + 2 × exactly two + 3 × all three; 137 − 96 − 2 × 7 = 27 |
| 16 | 16 | 1 and 2 are fixed in; the other 4 are free: 24 |
| 17 | (a) 24; (b) 21; (c) 28 | n(A ∪ B) = 51 − 20 = 31; n(B) = 31 − 10 + 3 = 24; only B = 24 − 3; exactly one = 7 + 21 |
| 18 | (a) 23; (b) 70; (c) 16 | n(A ∪ B ∪ C) = 36 + 37 + 35 − (14 + 12 + 13) + 8 = 77; exactly two = 14 + 12 + 13 − 3 × 8 = 15 |
| 19 | (a) 75%; (b) 85% | (a) n(M ∩ S) = 90 + 85 − n(M ∪ S) ≥ 90 + 85 − 100; (b) n(M ∪ S) = 90%, so 90 + 85 − 90 = 85 |
| 20 | (a) 9; (b) 42 | (a) 73 = 113 − 49 + n(all three); (b) only shampoo A = 35 − 11 − 21 + 9 = 12, and so on: 12 + 13 + 17 |