Standard difficulty · 20 questions · 40 marks
Show your working for Sections B and C. Answers are on the last page — try every question first!
Propositions and their Converses · AW-9M-PRP-2026-V1 · For parents — fold back or tear off before handing the sheet to your child.
| Q | Answer | Working |
|---|---|---|
| 1 | (d) either true or false, but not both | — |
| 2 | (a) If two angles of a triangle are equal, then the sides opposite them are equal. | swap the hypothesis and the conclusion |
| 3 | (d) right-angled | 802 + 842 = 13456 = 1162 |
| 4 | (c) 6 cm | sides opposite equal angles are equal |
| 5 | (a) 50 | 50 = 5 × 10, but 50 ÷ 15 leaves remainder 5 |
| 6 | (d) equal corresponding angles made by a transversal | the converse of the corresponding angles property |
| 7 | (a) 129° | opposite angles of a cyclic quadrilateral add up to 180°: 180° − 51° |
| 8 | (a) l ∥ m | 68° + 112° = 180° |
| 9 | If two triangles have equal areas, then they are congruent. False. | False: right triangles with legs 2 and 6, and 3 and 4, both have area 6 |
| 10 | No, it is obtuse-angled | 122 + 162 = 400 < 212 = 441 |
| 11 | 180 is divisible by 6 and 9, but not by 54 | 180 = 6 × 30 = 9 × 20, but 180 ÷ 54 leaves remainder 18; it works because 6 and 9 share the factor 3 |
| 12 | DF = EF | ∠E = 180° − 22° − 79° = 79°, so ∠D = ∠E and the sides opposite them are equal |
| 13 | No | ∠A + ∠C = 175°, not 180° |
| 14 | AE = 11 cm, DE = 16 cm | E is the midpoint of AC (converse of the mid-point theorem), so AE = 22 ÷ 2; then DE = ½ BC = 32 ÷ 2 |
| 15 | x = 24 | l ∥ m when the alternate angles are equal: 5x − 7 = 2x + 65 gives x = 24, and each angle is 113° |
| 16 | Yes | 48° + 36° + 96° = 180° |
| 17 | No, it is more than 90° | 402 + 422 = 3364 < 592 = 3481 |
| 18 | False: 4 × 4 = 16 | 16 = 8 × 2, but neither 4 nor 4 is a multiple of 8 |
| 19 | ∠D = 77°; no | ∠D = 360° − 105° − 109° − 69° = 77°; ∠A + ∠C = 174°, not 180° |
| 20 | DE = 180 m, AE = 200 m | converse of the mid-point theorem: E is the midpoint of AC, and DE = ½ BC |