Standard difficulty · 20 questions · 40 marks
Show your working for Sections B and C. Answers are on the last page — try every question first!
Quadrilaterals · AW-9M-QUD-2026-V1 · For parents — fold back or tear off before handing the sheet to your child.
| Q | Answer | Working |
|---|---|---|
| 1 | (d) 121° | 360° − 239° = 121° |
| 2 | (a) 130° | opposite angles are equal |
| 3 | (d) 25 cm | the diagonals bisect at right angles: √(72 + 242) = 25 |
| 4 | (d) 52 cm | √(202 + 482) = 52 |
| 5 | (c) 360° | — |
| 6 | (a) 168° | 15 parts = 360°, 1 part = 24° |
| 7 | (d) 19 cm | DE = BC ÷ 2 (mid-point theorem) |
| 8 | (c) A is true, but R is false. | A is true: DE = BC ÷ 2 = 6. R is false. |
| 9 | x = 23; 128°, 52°, 128°, 52° | adjacent angles are supplementary: 6x + 42 = 180 |
| 10 | x = 24; 27°, 153°, 27°, 153° | opposite angles are equal: −2x = −48 |
| 11 | x = 44; 44°, 62°, 88°, 166° | 6x + 96 = 360 |
| 12 | side 52 cm, perimeter 208 cm | half-diagonals 20 and 48 meet at 90°: side = √(202 + 482) = 52 |
| 13 | x = 6; AC = 118 cm | the diagonals bisect each other: AO = OC, so 3x = 18 |
| 14 | 27.5 cm | each side of the new triangle is half a side of the old one: 55 ÷ 2 |
| 15 | x = 19; 42 cm | the diagonals of a rectangle are equal: −3x = −57 |
| 16 | 35 cm, 39 cm, 35 cm, 39 cm | opposite sides are equal: 2 × (35 + y) = 148, y = 39 |
| 17 | 40 m | diagonal = √(602 + 802) = 100 m; 140 − 100 = 40 |
| 18 | 348 m | side = √(602 + 632) = 87 m; 4 × 87 |
| 19 | 138 m | each path is half the side it is parallel to (mid-point theorem) |
| 20 | 56°, 124° and 56° | adjacent angles add to 180°; opposite angles are equal |