Standard difficulty · 20 questions · 40 marks
Show your working for Sections B and C. Answers are on the last page — try every question first!
Math of Space: Surface Area and Volume · AW-9M-SAV-2026-V1 · For parents — fold back or tear off before handing the sheet to your child.
| Q | Answer | Working |
|---|---|---|
| 1 | (d) 50 cm | √(142 + 482) = √2500 = 50 |
| 2 | (c) 2,200 cm2 | πrl = 22/7 × 14 × 50 = 2,200 |
| 3 | (d) 61,600 cm2 | 4πr2 = 4 × 22/7 × 702 = 61,600 |
| 4 | (c) 1,848 cm2 | 3πr2 = 3 × 22/7 × 142 = 1,848 |
| 5 | (c) πrl | r = radius, l = slant height |
| 6 | (a) 179,666 2/3 cm3 | (4/3)πr3 = 4/3 × 22/7 × 353 = 179,666 2/3 |
| 7 | (c) 12,936 cm3 | (1/3)πr2h = 1/3 × 22/7 × 212 × 28 = 12,936 |
| 8 | (c) A is true, but R is false. | A is true: πrl = 22/7 × 56 × 70 = 12,320. R is false. |
| 9 | 2,816 cm2 | πr(l + r) = 22/7 × 14 × 64 = 2,816 |
| 10 | 155,232 cm3 | (2/3)πr3 = 2/3 × 22/7 × 423 = 155,232 |
| 11 | 56 cm | 4 × 22/7 × r2 = 39,424, so r2 = 3136, r = 56 |
| 12 | 15,400 cm3 | r = 35; (1/3) × 22/7 × 352 × 12 = 15,400 |
| 13 | 343 : 729 | volume goes as r3: 73 : 93 |
| 14 | 9 cm | (1/3) × 22/7 × 142 × h = 1,848, so h = 9 |
| 15 | 1241.856 litres | (2/3) × 22/7 × 843 = 1,241,856 cm3 = 1241.856 litres |
| 16 | 16,280 cm2 | r = 70; πrl = 22/7 × 70 × 74 = 16,280 |
| 17 | 264 m2; Rs 45,408 | πrl = 22/7 × 7 × 12 = 264 m2; × 172 = 45,408 |
| 18 | Rs 292,600 | 2πr2 = 2 × 22/7 × 352 = 7,700 m2; × 38 = 292,600 |
| 19 | 5,852 cm3 | one cone = (1/3) × 22/7 × 49 × 6 = 308; × 19 = 5,852 |
| 20 | 16 cones | (4/3)π × 23 ÷ ((1/3)π × 12 × 2) = 4 × 8 ÷ 2 = 16 |