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Class 12 Haloalkanes and Haloarenes worksheet

CBSE Chemistry. Naming and classes, SN1 and SN2, elimination, Wurtz and other named reactions, boiling points. Every sheet has 20 questions in three sections and an answer key, and the numbers change every time.

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Sample questions

Real questions from this chapter, as the app sets them. Tap Answer to see the answer and working.

Section A · multiple choice

  1. 1.

    The C–X bond in haloalkanes is polar because:

    1. both atoms have equal electronegativity
    2. the bond is ionic
    3. carbon is more electronegative
    4. the halogen is more electronegative than carbon
    Answer

    (d) the halogen is more electronegative than carbon

  2. 2.

    The IUPAC name of (CH₃)₂CHI is:

    1. 2-iodopropane
    2. 2-iodobutane
    3. 2-iodo-2-methylpropane
    4. 1-iodobutane
    Answer

    (a) 2-iodopropane

    common name: isopropyl iodide

  3. 3.

    2-chloropropane ((CH₃)₂CHCl) is a:

    1. tertiary (3°) alkyl halide
    2. primary (1°) alkyl halide
    3. vinylic halide
    4. secondary (2°) alkyl halide
    Answer

    (d) secondary (2°) alkyl halide

    count the carbons attached to the carbon bearing the halogen

Section B · short answer

  1. 4.

    Why are haloalkanes only slightly soluble in water, though they are polar?

    Answer

    To dissolve, energy is needed to break the hydrogen bonds between water molecules, and haloalkanes cannot form hydrogen bonds with water to release as much energy.

  2. 5.

    Give the IUPAC name and the common name of CH₃CH₂Br, and classify it as primary, secondary or tertiary.

    Answer

    bromoethane; ethyl bromide; primary (1°)

    count the carbons on the C–X carbon

Section C · long answer

  1. 6.

    Explain the SN2 mechanism with an example, and say how the structure of the halide affects its rate.

    Answer

    In SN2 the nucleophile attacks the carbon from the side opposite the leaving group in one step through a five-coordinate transition state; the configuration is inverted. E.g. CH₃Cl + OH⁻ → CH₃OH + Cl⁻, rate = k[CH₃Cl][OH⁻]. Bulky groups block the backside, so the order is CH₃X > 1° > 2° > 3°.

Fresh sheets for your child

In the app, every Haloalkanes and Haloarenes sheet is new: the app remembers the questions your child has already had and leaves them out. Print the sheet as a PDF, or use notebook mode and write the answers in a notebook.

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