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Class 12 Alternating Current worksheet
CBSE Physics. rms values, reactance, impedance, resonance, power factor, transformers. Every sheet has 20 questions in three sections and an answer key, and the numbers change every time.
Sample questions
Real questions from this chapter, as the app sets them. Tap Answer to see the answer and working.
Section A · multiple choice
- 1.
The peak value of a 110 V (rms) supply is:
- 110/√2 V
- 110 V
- 220 V
- 110√2 V
Answer
(d) 110√2 V
V₀ = √2 V_rms
- 2.
The reactance of a 18 × 10⁻² H inductor at an angular frequency of 950 rad/s is:
- 171 Ω
- 0.00585 Ω
- 342 Ω
- 17.1 Ω
Answer
(a) 171 Ω
X_L = ωL
- 3.
The reactance of a 1 μF capacitor at an angular frequency of 800 rad/s is:
- 12,500 Ω
- 0.0008 Ω
- 625 Ω
- 1,250 Ω
Answer
(d) 1,250 Ω
X_C = 1/(ωC)
Section B · short answer
- 4.
A 150 V (rms) supply drives a series circuit with R = 12 Ω, X_L = 58 Ω and X_C = 49 Ω. Find the current and the voltage across each element.
Answer
I = 10 A; V_R = 120 V, V_L = 580 V, V_C = 490 V
Z = 15 Ω
- 5.
For a series circuit with R = 20 Ω, X_L = 30 Ω and X_C = 51 Ω across 290 V (rms), find the power factor and the average power.
Answer
20/29; 2,000 W
P = V_rms I_rms cos φ = I²R
Section C · long answer
- 6.
A series LCR circuit has R = 80 Ω, X_L = 15 Ω and X_C = 99 Ω across a 464 V (rms) supply. Find the impedance, the current, the power factor, the average power and the voltage across each element.
Answer
Z = 116 Ω; I = 4 A; cos φ = 20/29; P = 1,280 W; V_R = 320 V, V_L = 60 V, V_C = 396 V
Z = √(R² + (X_L − X_C)²)
Fresh sheets for your child
In the app, every Alternating Current sheet is new: the app remembers the questions your child has already had and leaves them out. Print the sheet as a PDF, or use notebook mode and write the answers in a notebook.
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