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Class 12 Magnetism and Matter worksheet
CBSE Physics. Bar magnets, torque and energy in a field, magnetisation, dia-, para- and ferromagnetism. Every sheet has 20 questions in three sections and an answer key, and the numbers change every time.
Sample questions
Real questions from this chapter, as the app sets them. Tap Answer to see the answer and working.
Section A · multiple choice
- 1.
A bar magnet of magnetic moment 2 A m² makes 150° with a uniform field of 6 × 10⁻² T. The torque on it is:
- 6 × 10⁻⁴ N m
- 0.12 N m
- 0 N m
- 0.06 N m
Answer
(d) 0.06 N m
τ = mB sin θ
- 2.
The magnetic field 20 cm from the centre of a short bar magnet of moment 9 A m², on its axis, is: (μ₀ = 4π × 10⁻⁷ T m/A)
- 1.125 × 10⁻⁴ T
- 2.25 × 10⁻⁶ T
- 2.25 × 10⁻⁴ T
- 4.5 × 10⁻³ T
Answer
(c) 2.25 × 10⁻⁴ T
B = (μ₀/4π) × 2m/r³
- 3.
A magnet of moment 2 A m² makes 90° with a field of 2 × 10⁻² T. Its potential energy is:
- 0.04 J
- −0.02 J
- −0.04 J
- 0 J
Answer
(d) 0 J
U = −mB cos θ
Section B · short answer
- 4.
A coil of 226 turns and area 26 cm² carries 1 A. Find its magnetic moment and the largest torque on it in a field of 9 × 10⁻² T.
Answer
0.5876 A m²; 0.052884 N m
m = NIA; τmax = mB
- 5.
A short bar magnet has moment 8 A m². Find the field 5 cm from its centre (a) on its axis, (b) on its equatorial line. (μ₀ = 4π × 10⁻⁷ T m/A)
Answer
(a) 0.0128 T; (b) 6.4 × 10⁻³ T
axis: 2m/r³ × 10⁻⁷; equator: m/r³ × 10⁻⁷
Section C · long answer
- 6.
A short bar magnet of moment 1 A m² lies along the x-axis with its centre at the origin. Find the field at (20 cm, 0) and at (0, 20 cm), and the ratio of the two. (μ₀ = 4π × 10⁻⁷ T m/A)
Answer
2.5 × 10⁻⁵ T along the axis; 1.25 × 10⁻⁵ T, opposite to the moment; ratio 2 : 1
B(axis) = 2m/r³ × 10⁻⁷, B(equator) = m/r³ × 10⁻⁷
Fresh sheets for your child
In the app, every Magnetism and Matter sheet is new: the app remembers the questions your child has already had and leaves them out. Print the sheet as a PDF, or use notebook mode and write the answers in a notebook.
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