Worksheets › Class 12 › Electrostatic Potential and Capacitance
Class 12 Electrostatic Potential and Capacitance worksheet
CBSE Physics. Potential, potential energy, capacitors in series and parallel, dielectrics, energy stored. Every sheet has 20 questions in three sections and an answer key, and the numbers change every time.
Sample questions
Real questions from this chapter, as the app sets them. Tap Answer to see the answer and working.
Section A · multiple choice
- 1.
The potential 15 cm from a point charge of −2 μC is: (k = 9 × 10⁹ N m²/C²)
- 1.2 × 10⁵ V
- −8 × 10⁵ V
- −1,200 V
- −1.2 × 10⁵ V
Answer
(d) −1.2 × 10⁵ V
V = kq/r
- 2.
The work needed to carry a charge of 9 μC from a point at 470 V to a point at 500 V is:
- 2.7 × 10⁻⁴ J
- −2.7 × 10⁻⁴ J
- 8.73 × 10⁻³ J
- 0.27 J
Answer
(a) 2.7 × 10⁻⁴ J
W = q(V_B − V_A) = 9 × 10⁻⁶ × (30)
- 3.
The equivalent capacitance of 1 μF, 10 μF joined in series is:
- 10 μF
- 11 μF
- 0.91 μF
- 1.82 μF
Answer
(c) 0.91 μF
1/C = Σ 1/Cᵢ
Section B · short answer
- 4.
Charges of −2 μC and −8 μC are at x = 0 and x = 24 cm. Find the potential at x = 16 cm. (k = 9 × 10⁹ N m²/C²)
Answer
−1.0125 × 10⁶ V
V = k(q₁/r₁ + q₂/r₂), with r₁ = 16 cm and r₂ = 8 cm
- 5.
9 μF and 5 μF capacitors in parallel are joined in series with a 7 μF capacitor across 190 V. Find the equivalent capacitance and the charge on the 7 μF capacitor.
Answer
4.67 μF; 8.87 × 10⁻⁴ C
parallel pair 14 μF; series with 7 μF; Q = CV
Section C · long answer
- 6.
11 μF and 12 μF capacitors in series are joined in parallel with 8 μF; this group is in series with 11 μF, across 160 V. Find the equivalent capacitance, the total charge and the energy stored.
Answer
6.11 μF; 9.77 × 10⁻⁴ C; 0.0782 J
group = 5.74 + 8 = 13.74 μF
Fresh sheets for your child
In the app, every Electrostatic Potential and Capacitance sheet is new: the app remembers the questions your child has already had and leaves them out. Print the sheet as a PDF, or use notebook mode and write the answers in a notebook.
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